Integrand size = 26, antiderivative size = 56 \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=\frac {a^2 x}{c}-\frac {a^2 \text {arctanh}(\sin (e+f x))}{c f}-\frac {4 a^2 \tan (e+f x)}{c f (1-\sec (e+f x))} \]
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Time = 0.23 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.00, number of steps used = 8, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {3988, 3862, 8, 3879, 3874, 3855} \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=-\frac {a^2 \text {arctanh}(\sin (e+f x))}{c f}-\frac {4 a^2 \tan (e+f x)}{c f (1-\sec (e+f x))}+\frac {a^2 x}{c} \]
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Rule 8
Rule 3855
Rule 3862
Rule 3874
Rule 3879
Rule 3988
Rubi steps \begin{align*} \text {integral}& = \frac {\int \left (\frac {a^2}{1-\sec (e+f x)}+\frac {2 a^2 \sec (e+f x)}{1-\sec (e+f x)}+\frac {a^2 \sec ^2(e+f x)}{1-\sec (e+f x)}\right ) \, dx}{c} \\ & = \frac {a^2 \int \frac {1}{1-\sec (e+f x)} \, dx}{c}+\frac {a^2 \int \frac {\sec ^2(e+f x)}{1-\sec (e+f x)} \, dx}{c}+\frac {\left (2 a^2\right ) \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{c} \\ & = -\frac {3 a^2 \tan (e+f x)}{c f (1-\sec (e+f x))}-\frac {a^2 \int -1 \, dx}{c}-\frac {a^2 \int \sec (e+f x) \, dx}{c}+\frac {a^2 \int \frac {\sec (e+f x)}{1-\sec (e+f x)} \, dx}{c} \\ & = \frac {a^2 x}{c}-\frac {a^2 \text {arctanh}(\sin (e+f x))}{c f}-\frac {4 a^2 \tan (e+f x)}{c f (1-\sec (e+f x))} \\ \end{align*}
Leaf count is larger than twice the leaf count of optimal. \(201\) vs. \(2(56)=112\).
Time = 1.61 (sec) , antiderivative size = 201, normalized size of antiderivative = 3.59 \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=-\frac {a^{3/2} \tan (e+f x) \left (4 \sqrt {c} \left (\sqrt {a} \sqrt {1-\sec (e+f x)} (1+\sec (e+f x))+\arcsin \left (\frac {\sqrt {a (1+\sec (e+f x))}}{\sqrt {2} \sqrt {a}}\right ) \sec (e+f x) \sqrt {a (1+\sec (e+f x))} \sin ^2\left (\frac {1}{2} (e+f x)\right )\right )-\text {arctanh}\left (\frac {\sqrt {-a c \tan ^2(e+f x)}}{\sqrt {a} \sqrt {c}}\right ) \sqrt {1-\sec (e+f x)} \sqrt {-a c \tan ^2(e+f x)}\right )}{c^{3/2} f (1-\sec (e+f x))^{3/2} (1+\sec (e+f x))} \]
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Time = 0.49 (sec) , antiderivative size = 64, normalized size of antiderivative = 1.14
method | result | size |
derivativedivides | \(\frac {4 a^{2} \left (\frac {1}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )}+\frac {\ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{4}+\frac {\arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}-\frac {\ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}{4}\right )}{f c}\) | \(64\) |
default | \(\frac {4 a^{2} \left (\frac {1}{\tan \left (\frac {f x}{2}+\frac {e}{2}\right )}+\frac {\ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{4}+\frac {\arctan \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{2}-\frac {\ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}{4}\right )}{f c}\) | \(64\) |
parallelrisch | \(\frac {a^{2} \left (4+\tan \left (\frac {f x}{2}+\frac {e}{2}\right ) f x +\ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )-\ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )\right )}{f c \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}\) | \(81\) |
risch | \(\frac {a^{2} x}{c}+\frac {8 i a^{2}}{f c \left ({\mathrm e}^{i \left (f x +e \right )}-1\right )}+\frac {a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}-i\right )}{c f}-\frac {a^{2} \ln \left ({\mathrm e}^{i \left (f x +e \right )}+i\right )}{c f}\) | \(82\) |
norman | \(\frac {\frac {a^{2} x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{3}}{c}-\frac {4 a^{2}}{c f}+\frac {4 a^{2} \tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}}{c f}-\frac {a^{2} x \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}{c}}{\left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )^{2}-1\right ) \tan \left (\frac {f x}{2}+\frac {e}{2}\right )}+\frac {a^{2} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )-1\right )}{c f}-\frac {a^{2} \ln \left (\tan \left (\frac {f x}{2}+\frac {e}{2}\right )+1\right )}{c f}\) | \(145\) |
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Time = 0.26 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.55 \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=\frac {2 \, a^{2} f x \sin \left (f x + e\right ) - a^{2} \log \left (\sin \left (f x + e\right ) + 1\right ) \sin \left (f x + e\right ) + a^{2} \log \left (-\sin \left (f x + e\right ) + 1\right ) \sin \left (f x + e\right ) + 8 \, a^{2} \cos \left (f x + e\right ) + 8 \, a^{2}}{2 \, c f \sin \left (f x + e\right )} \]
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\[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=- \frac {a^{2} \left (\int \frac {2 \sec {\left (e + f x \right )}}{\sec {\left (e + f x \right )} - 1}\, dx + \int \frac {\sec ^{2}{\left (e + f x \right )}}{\sec {\left (e + f x \right )} - 1}\, dx + \int \frac {1}{\sec {\left (e + f x \right )} - 1}\, dx\right )}{c} \]
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Leaf count of result is larger than twice the leaf count of optimal. 153 vs. \(2 (54) = 108\).
Time = 0.28 (sec) , antiderivative size = 153, normalized size of antiderivative = 2.73 \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=\frac {a^{2} {\left (\frac {2 \, \arctan \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1}\right )}{c} + \frac {\cos \left (f x + e\right ) + 1}{c \sin \left (f x + e\right )}\right )} - a^{2} {\left (\frac {\log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} + 1\right )}{c} - \frac {\log \left (\frac {\sin \left (f x + e\right )}{\cos \left (f x + e\right ) + 1} - 1\right )}{c} - \frac {\cos \left (f x + e\right ) + 1}{c \sin \left (f x + e\right )}\right )} + \frac {2 \, a^{2} {\left (\cos \left (f x + e\right ) + 1\right )}}{c \sin \left (f x + e\right )}}{f} \]
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Time = 0.31 (sec) , antiderivative size = 77, normalized size of antiderivative = 1.38 \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=\frac {\frac {{\left (f x + e\right )} a^{2}}{c} - \frac {a^{2} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) + 1 \right |}\right )}{c} + \frac {a^{2} \log \left ({\left | \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right ) - 1 \right |}\right )}{c} + \frac {4 \, a^{2}}{c \tan \left (\frac {1}{2} \, f x + \frac {1}{2} \, e\right )}}{f} \]
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Time = 14.14 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.82 \[ \int \frac {(a+a \sec (e+f x))^2}{c-c \sec (e+f x)} \, dx=\frac {a^2\,x}{c}-\frac {a^2\,\left (2\,\mathrm {atanh}\left (\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )\right )-\frac {4}{\mathrm {tan}\left (\frac {e}{2}+\frac {f\,x}{2}\right )}\right )}{c\,f} \]
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